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JavaScript: Get the sum of the powers of all the numbers from start to end

JavaScript fundamental (ES6 Syntax): Exercise-135 with Solution

Write a JavaScript program to get the sum of the powers of all the numbers from start to end (both inclusive).

  • Use Array.prototype.fill() to create an array of all the numbers in the target range.
  • Use Array.prototype.map() and the exponent operator (**) to raise them to power and Array.prototype.reduce() to add them together.
  • Omit the second argument, power, to use a default power of 2.
  • Omit the third argument, start, to use a default starting value of 1.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);

console.log(sumPower(10));
console.log(sumPower(10, 3));
console.log(sumPower(10, 3, 5));

Sample Output:

385
3025
2925

Pictorial Presentation:

JavaScript Fundamental: Get the sum of the powers of all the numbers from start to end.
JavaScript Fundamental: Get the sum of the powers of all the numbers from start to end.

Flowchart:

flowchart: Get the sum of the powers of all the numbers from start to end

Live Demo:

See the Pen javascript-basic-exercise-135-1 by w3resource (@w3resource) on CodePen.


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Next: Write a JavaScript program to generate all permutations of a string (contains duplicates).

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JavaScript: Tips of the Day

Chunks an array into n smaller arrays

Example:

const tips_chunkIntoN = (arr, n) => {
  const size = Math.ceil(arr.length / n);
  return Array.from({ length: n }, (v, i) =>
    arr.slice(i * size, i * size + size)
  );
}
console.log(tips_chunkIntoN([1, 2, 3, 4, 5, 6, 7,8], 4)); 

Output:

[[1,2],[3,4],[5,6],[7,8]]