# JavaScript: Get the n minimum elements from the provided array

## JavaScript fundamental (ES6 Syntax): Exercise-176 with Solution

Write a JavaScript program to get the n minimum elements from the provided array.
If n is greater than or equal to the provided array's length, return the original array (sorted in ascending order).

• Use Array.prototype.sort() combined with the spread operator (...) to create a shallow clone of the array and sort it in ascending order.
• Use Array.prototype.slice() to get the specified number of elements.
• Omit the second argument, n, to get a one-element array.
• If n is greater than or equal to the provided array's length, then return the original array (sorted in ascending order).

Sample Solution:

JavaScript Code:

``````// Define a function 'minN' that takes an array 'arr' and an optional parameter 'n' with a default value of 1
const minN = (arr, n = 1) =>
// Create a shallow copy of the array 'arr', sort it in ascending order, and then extract the first 'n' elements
[...arr].sort((a, b) => a - b).slice(0, n);

// Log the smallest element from the array [1, 2, 3]
console.log(minN([1, 2, 3]));
// Log the smallest '2' elements from the array [1, 2, 3]
console.log(minN([1, 2, 3], 2));
```
```

Output:

```[1]
[1,2]
```

Visual Presentation:

Flowchart:

Live Demo:

See the Pen javascript-basic-exercise-176-1 by w3resource (@w3resource) on CodePen.

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