JavaScript: Return true if the given number is even, false otherwise

JavaScript fundamental (ES6 Syntax): Exercise-199 with Solution

Check If Even Number

Write a JavaScript program that returns true if the given number is even, false otherwise.

• Checks whether a number is odd or even using the modulo (%) operator.
• Returns true if the number is even, false if the number is odd.

Sample Solution:

JavaScript Code:

// Define a function 'isEven' that checks if the given number 'num' is even
const isEven = num =>
  // Check if the remainder of 'num' divided by 2 is equal to 0
  num % 2 === 0;

// Test cases to check if the numbers are even
console.log(isEven(3));   // false (the number is odd)
console.log(isEven(32));  // true (the number is even)
console.log(isEven(1));   // false (the number is odd)
console.log(isEven(0));   // true (zero is considered an even number)

Output:

false
true
false
true

Visual Presentation:

Flowchart:

Live Demo:

See the Pen javascript-basic-exercise-199-1 by w3resource (@w3resource) on CodePen.

For more Practice: Solve these Related Problems:

• Write a JavaScript program that returns true if a given number is even by using the modulo operator.
• Write a JavaScript function that tests a number for evenness and handles non-numeric input gracefully.
• Write a JavaScript program that determines even numbers in an array and returns a filtered array of even values.
• Write a JavaScript function that checks if a number is even by converting it to an integer and applying modulus 2.

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