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JavaScript: Return true if the given number is even, false otherwise

JavaScript fundamental (ES6 Syntax): Exercise-199 with Solution

Write a JavaScript program that will return true if the given number is even, false otherwise.

  • Checks whether a number is odd or even using the modulo (%) operator.
  • Returns true if the number is even, false if the number is odd.

Sample Solution:

JavaScript Code:

//#Source https://bit.ly/2neWfJ2 
const isEven = num => num % 2 === 0;

console.log(isEven(3));
console.log(isEven(32));
console.log(isEven(1));
console.log(isEven(0));

Sample Output:

false
true
false
true

Pictorial Presentation:

JavaScript Fundamental: Return true if the given number is even, false otherwise.
JavaScript Fundamental: Return true if the given number is even, false otherwise.
JavaScript Fundamental: Return true if the given number is even, false otherwise.
JavaScript Fundamental: Return true if the given number is even, false otherwise.

Flowchart:

flowchart: Return true if the given number is even, false otherwise

Live Demo:

See the Pen javascript-basic-exercise-199-1 by w3resource (@w3resource) on CodePen.


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Next: Write a JavaScript program that will return true if a value is an empty object, collection, map or set, has no enumerable properties or is any type that is not considered a collection.

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JavaScript: Tips of the Day

How to check whether a string contains a substring in JavaScript?

ECMAScript 6 introduced String.prototype.includes:

const string = "foo";
const substring = "oo";

console.log(string.includes(substring));

includes doesn't have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found:

var string = "foo";
var substring = "oo";

console.log(string.indexOf(substring) !== -1);

Ref: https://bit.ly/3fFFgZv