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JavaScript: Check whether there is at least one element which occurs in two given sorted arrays of integers

JavaScript Basic: Exercise-100 with Solution

Write a JavaScript program to check whether there is at least one element which occurs in two given sorted arrays of integers.

Pictorial Presentation:

JavaScript: Check whether there is at least one element which occurs in two given sorted arrays of integers.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title> Check whether there is at least one element which occurs in two given sorted arrays of integers</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function check_common_element(arra1, arra2) {
  for (var i = 0; i < arra1.length; i++)
  {
    if (arra2.indexOf(arra1[i]) != -1) 
      return true;
  }
  return false;
}
console.log(check_common_element([1,2,3], [3,4,5]));   
console.log(check_common_element([1,2,3], [5,6,7]));

Sample Output:

true
false

Flowchart:

Flowchart: JavaScript - Check whether there is at least one element which occurs in two given sorted arrays of integers

ES6 Version:

function check_common_element(arra1, arra2) {
  for (let i = 0; i < arra1.length; i++)
  {
    if (arra2.includes(arra1[i])) 
      return true;
  }
  return false;
}
console.log(check_common_element([1,2,3], [3,4,5]));   
console.log(check_common_element([1,2,3], [5,6,7]));

Live Demo:

See the Pen javascript-basic-exercise-100 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to check whether it is possible to rearrange characters of a given string in such way that it will become equal to another given string.
Next: Write a JavaScript program to check whether a given string contains only Latin letters and no two uppercase and no two lowercase letters are in adjacent positions.

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JavaScript: Tips of the Day

Promise object

const myPromise = () => Promise.resolve('I have resolved!');

function firstFunction() {
  myPromise().then(res => console.log(res));
  console.log('second');
}

async function secondFunction() {
  console.log(await myPromise());
  console.log('second');
}

firstFunction();
secondFunction();

With a promise, we basically say I want to execute this function, but I'll put it aside for now while it's running since this might take a while. Only when a certain value is resolved (or rejected), and when the call stack is empty, I want to use this value.
We can get this value with both .then and the await keyword in an async function. Although we can get a promise's value with both .then and await, they work a bit differently.
In the firstFunction, we (sort of) put the myPromise function aside while it was running, but continued running the other code, which is console.log('second') in this case. Then, the function resolved with the string I have resolved, which then got logged after it saw that the callstack was empty.
With the await keyword in secondFunction, we literally pause the execution of an async function until the value has been resolved before moving to the next line.
This means that it waited for the myPromise to resolve with the value I have resolved, and only once that happened, we moved to the next line: second got logged.

Ref: https://bit.ly/3jFRBje