JavaScript: Divide an integer by another integer as long as the result is an integer and return the result
JavaScript Basic: Exercise-106 with Solution
Write a JavaScript program to divide an integer by another integer as long as the result is an integer and return the result.
Sample Solution:
JavaScript Code:
// Function to divide a number by a digit
function divide_digit(num, d) {
// Check if divisor is 1, return the number itself
if (d == 1)
return num;
else {
// Loop to divide the number by the divisor until not divisible
while (num % d === 0) {
num /= d; // Divide the number by the divisor
}
return num; // Return the final divided number
}
}
// Example usage of the function with different numbers and divisors
console.log(divide_digit(-12, 2)); // Output: -3
console.log(divide_digit(13, 2)); // Output: 13
console.log(divide_digit(13, 1)); // Output: 13
Output:
-3 13 13
Live Demo:
See the Pen javascript-basic-exercise-106 by w3resource (@w3resource) on CodePen.
Flowchart:
ES6 Version:
// Function to divide a number by a divisor until it's not divisible anymore
const divide_digit = (num, d) => {
if (d === 1) // If the divisor is 1, return the number as it is
return num;
else {
while (num % d === 0) { // Loop while the number is divisible by the divisor
num /= d; // Divide the number by the divisor
}
return num; // Return the resulting number after division
}
};
// Example usage of the function
console.log(divide_digit(-12, 2)); // Output: -3 (divided -12 by 2 until it's not divisible)
console.log(divide_digit(13, 2)); // Output: 13 (13 is not divisible by 2)
console.log(divide_digit(13, 1)); // Output: 13 (divisor is 1, returns the number as it is)
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