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JavaScript: Create the dot products of two given 3D vectors

JavaScript Basic: Exercise-108 with Solution

Write a JavaScript program to create the dot products of two given 3D vectors.

Note: The dot product is the sum of the products of the corresponding entries of the two sequences of numbers.

Sample Solution:

JavaScript Code:

// Function to calculate the dot product of two vectors in 3D space
function dot_product(vector1, vector2) {
  var result = 0; // Initialize the variable to store the dot product result

  // Loop through each component of the vectors and calculate the dot product
  for (var i = 0; i < 3; i++) {
    result += vector1[i] * vector2[i]; // Sum the products of corresponding components
  }

  return result; // Return the calculated dot product
}

// Examples of calculating dot products of given vectors
console.log(dot_product([1, 2, 3], [1, 2, 3])); // Output: 14 (1*1 + 2*2 + 3*3 = 14)
console.log(dot_product([2, 4, 6], [2, 4, 6])); // Output: 56 (2*2 + 4*4 + 6*6 = 56)
console.log(dot_product([1, 1, 1], [0, 1, -1])); // Output: 0 (1*0 + 1*1 + 1*(-1) = 0) 

Output:

14
56
0

Live Demo:

See the Pen javascript-basic-exercise-109 by w3resource (@w3resource) on CodePen.


Flowchart:

Flowchart: JavaScript - Create the dot products of two given 3D vectors

ES6 Version:

// Function to calculate the dot product of two 3-dimensional vectors
const dot_product = (vector1, vector2) => {
  let result = 0; // Variable to store the dot product result

  // Loop through the vectors and calculate the dot product
  for (let i = 0; i < 3; i++) {
    result += vector1[i] * vector2[i]; // Compute the dot product for each element pair
  }

  return result; // Return the final dot product value
};

// Example usage of the function
console.log(dot_product([1, 2, 3], [1, 2, 3])); // Output: 14 (1*1 + 2*2 + 3*3 = 14)
console.log(dot_product([2, 4, 6], [2, 4, 6])); // Output: 56 (2*2 + 4*4 + 6*6 = 56)
console.log(dot_product([1, 1, 1], [0, 1, -1])); // Output: 0 (1*0 + 1*1 + 1*(-1) = 0)

Improve this sample solution and post your code through Disqus.

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