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JavaScript: Compute the sum of all digits that occur in a given string

JavaScript Basic: Exercise-147 with Solution

Write a JavaScript program to compute the sum of all digits that occur in a given string.

Pictorial Presentation:

JavaScript: Compute the sum of all digits that occur in a given string.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>Compute the sum of all digits that occur in a given string.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function sum_digits_from_string(dstr) {
  var dsum = 0;

  for (var i = 0; i < dstr.length; i++)
  {

    if (/[0-9]/.test(dstr[i])) dsum += parseInt(dstr[i])
  }
  return dsum;
}

console.log(sum_digits_from_string("abcd12efg9"))
console.log(sum_digits_from_string("w3resource"))

Sample Output:

12
3

Flowchart:

Flowchart: JavaScript - Compute the sum of all digits that occur in a given string

ES6 Version:

function sum_digits_from_string(dstr) {
  let dsum = 0;

  for (let i = 0; i < dstr.length; i++)
  {

    if (/[0-9]/.test(dstr[i])) dsum += parseInt(dstr[i])
  }
  return dsum;
}

console.log(sum_digits_from_string("abcd12efg9"))
console.log(sum_digits_from_string("w3resource"))

Live Demo:

See the Pen javascript-basic-exercise-147 by w3resource (@w3resource) on CodePen.


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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925 

Output:

385
3025
2925