# JavaScript: Compute the sum of all digits that occur in a given string

## JavaScript Basic: Exercise-147 with Solution

Write a JavaScript program to compute the sum of all digits that occur in a given string.

Pictorial Presentation:

Sample Solution:

HTML Code:

``````<!DOCTYPE html>
<html>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>Compute the sum of all digits that occur in a given string.</title>
<body>

</body>
</html>
```
```

JavaScript Code:

``````function sum_digits_from_string(dstr) {
var dsum = 0;

for (var i = 0; i < dstr.length; i++)
{

if (/[0-9]/.test(dstr[i])) dsum += parseInt(dstr[i])
}
return dsum;
}

console.log(sum_digits_from_string("abcd12efg9"))
console.log(sum_digits_from_string("w3resource"))
``````

Sample Output:

```12
3
```

Flowchart:

ES6 Version:

``````function sum_digits_from_string(dstr) {
let dsum = 0;

for (let i = 0; i < dstr.length; i++)
{

if (/[0-9]/.test(dstr[i])) dsum += parseInt(dstr[i])
}
return dsum;
}

console.log(sum_digits_from_string("abcd12efg9"))
console.log(sum_digits_from_string("w3resource"))
``````

Live Demo:

See the Pen javascript-basic-exercise-147 by w3resource (@w3resource) on CodePen.

Improve this sample solution and post your code through Disqus

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿

## JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

```const sumPower = (end, power = 2, start = 1) =>
Array(end + 1 - start)
.fill(0)
.map((x, i) => (i + start) ** power)
.reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925
```

Output:

```385
3025
2925
```