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JavaScript: Find the larger number from the two given positive integers

JavaScript Basic: Exercise-34 with Solution

Write a JavaScript program to find the larger number from the two given positive integers, the two numbers are in the range 40..60 inclusive.

Pictorial Presentation:

JavaScript: Find the larger number from the two given positive integers

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JavaScript program to find the larger number from the two given positive integers, the two numbers  are in the range 40..60 inclusive.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function max_townums_range(x, y){	
if( (x >= 40) && (x <= 60) && (y >= 40 && y <= 60) ){
if(x === y){
return "Numbers are the same";
}else if (x > y){
return x;
}else{
return y;
}
}else{
return "Numbers don't fit in range";
}
}

console.log(max_townums_range(45, 60));
console.log(max_townums_range(25, 60));
console.log(max_townums_range(45, 80));

Output :

60
Numbers don't fit in range
Numbers don't fit in range

Flowchart:

Flowchart: JavaScript - Find the larger number from the two given positive integers

ES6 Version:

function max_townums_range(x, y) {
  if (x >= 40 && x <= 60 && y >= 40 && y <= 60) {
    if (x === y) {
      return "Numbers are the same";
    } else if (x > y) {
      return x;
    } else {
      return y;
    }
  } else {
    return "Numbers don't fit in range";
  }
}

console.log(max_townums_range(45, 60));
console.log(max_townums_range(25, 60));
console.log(max_townums_range(45, 80));

Live Demo:

See the Pen javascript-basic-exercise-34 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to check if two numbers are in range 40..60 or in the range 70..100 inclusive.
Next: Write a JavaScript program to check a given string contains 2 to 4 numbers of a specified character.

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JavaScript: Tips of the Day

Promise object

const myPromise = () => Promise.resolve('I have resolved!');

function firstFunction() {
  myPromise().then(res => console.log(res));
  console.log('second');
}

async function secondFunction() {
  console.log(await myPromise());
  console.log('second');
}

firstFunction();
secondFunction();

With a promise, we basically say I want to execute this function, but I'll put it aside for now while it's running since this might take a while. Only when a certain value is resolved (or rejected), and when the call stack is empty, I want to use this value.
We can get this value with both .then and the await keyword in an async function. Although we can get a promise's value with both .then and await, they work a bit differently.
In the firstFunction, we (sort of) put the myPromise function aside while it was running, but continued running the other code, which is console.log('second') in this case. Then, the function resolved with the string I have resolved, which then got logged after it saw that the callstack was empty.
With the await keyword in secondFunction, we literally pause the execution of an async function until the value has been resolved before moving to the next line.
This means that it waited for the myPromise to resolve with the value I have resolved, and only once that happened, we moved to the next line: second got logged.

Ref: https://bit.ly/3jFRBje