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JavaScript: Check from two given integers whether one of them is 8 or their sum or difference is 8

JavaScript Basic: Exercise-40 with Solution

Write a JavaScript program to check from two given integers whether one of them is 8 or their sum or difference is 8.

Pictorial Presentation:

JavaScript: Check from two given integers whether one of them is 8 or their sum or difference is 8

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>Write a JavaScript program to check from two given integers whether one of them is 8 or their sum or difference is 8.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function check8(x, y) {
  if (x == 8 || y == 8) {
    return true;
  }

  if (x + y == 8 || Math.abs(x - y) == 8)
  {
    return true;
  }

  return false;
}

console.log(check8(7, 8));
console.log(check8(16, 8));
console.log(check8(24, 32));
console.log(check8(17, 18));

Sample Output:

true
true
true
false

Flowchart:

Flowchart: JavaScript - Check from two given integers whether one of them is 8 or their sum or difference is 8

ES6 Version:

function check8(x, y) {
  if (x == 8 || y == 8) {
    return true;
  }

  if (x + y == 8 || Math.abs(x - y) == 8)
  {
    return true;
  }

  return false;
}

console.log(check8(7, 8));
console.log(check8(16, 8));
console.log(check8(24, 32));
console.log(check8(17, 18));

Live Demo:

See the Pen JavaScript: Check from two given integers - basic-ex-40 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to compute the sum of the two given integers, If the sum is in the range 50..80 return 65 other wise return 80.
Next: Write a JavaScript program to check three given numbers, if the three numbers are same return 30 otherwise return 20 and if two numbers are same return 40.

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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925 

Output:

385
3025
2925