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JavaScript: Check whether three given numbers are increasing in strict mode or in soft mode

JavaScript Basic: Exercise-42 with Solution

Write a JavaScript program to check whether three given numbers are increasing in strict mode or in soft mode.
Note: Strict mode -> 10, 15, 31 : Soft mode -> 24, 22, 31 or 22, 22, 31

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>Write a JavaScript program to check whether three given numbers are increasing in strict mode or in soft mode.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function number_order(x, y, z ) {
  if ( y > x && z > y) 
  {
    return "strict mode";    
  }
  else if(z > y) 
   return "Soft mode";
  else
    return "Undefinded";
}

console.log(number_order(10,15,31));
console.log(number_order(24,22,31));
console.log(number_order(50,21,15));

Sample Output:

strict mode
Soft mode
Undefinded

Flowchart:

Flowchart: JavaScript - Check whether three given numbers are increasing in strict mode or in soft mode

ES6 Version:

function number_order(x, y, z ) {
  if ( y > x && z > y) 
  {
    return "strict mode";    
  }
  else if(z > y) 
   return "Soft mode";
  else
    return "Undefinded";
}

console.log(number_order(10,15,31));
console.log(number_order(24,22,31));
console.log(number_order(50,21,15));

Live Demo:

See the Pen JavaScript: Check whether three given numbers are increasing in strict mode - basic-ex-42 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to check three given numbers, if the three numbers are same return 30 otherwise return 20 and if two numbers are same return 40.
Next: Write a JavaScript program to check from three given numbers (non negative integers) that two or all of them have the same rightmost digit.

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JavaScript: Tips of the Day

Promise object

const myPromise = () => Promise.resolve('I have resolved!');

function firstFunction() {
  myPromise().then(res => console.log(res));
  console.log('second');
}

async function secondFunction() {
  console.log(await myPromise());
  console.log('second');
}

firstFunction();
secondFunction();

With a promise, we basically say I want to execute this function, but I'll put it aside for now while it's running since this might take a while. Only when a certain value is resolved (or rejected), and when the call stack is empty, I want to use this value.
We can get this value with both .then and the await keyword in an async function. Although we can get a promise's value with both .then and await, they work a bit differently.
In the firstFunction, we (sort of) put the myPromise function aside while it was running, but continued running the other code, which is console.log('second') in this case. Then, the function resolved with the string I have resolved, which then got logged after it saw that the callstack was empty.
With the await keyword in secondFunction, we literally pause the execution of an async function until the value has been resolved before moving to the next line.
This means that it waited for the myPromise to resolve with the value I have resolved, and only once that happened, we moved to the next line: second got logged.

Ref: https://bit.ly/3jFRBje