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JavaScript: Check from two given non-negative integers that whether one of the number is multiple of 7 or 11

JavaScript Basic: Exercise-46 with Solution

Write a JavaScript program to check two given non-negative integers that whether one of the number (not both) is multiple of 7 or 11.

Pictorial Presentation:

JavaScript: Check from two given non-negative integers that whether one of the number is multiple of 7 or 11

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JavaScript program to check two given non-negative integers that whether one of the number (not both) is multiple of 7 or 11.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function valCheck (a, b) {
if (!((a % 7 == 0 || a % 11 == 0) && (b % 7 == 0 || b % 11 == 0))) {
return ((a % 7 == 0 || a % 11 == 0) || (b % 7 == 0 || b % 11 == 0));
}
else
return false;
}
console.log(valCheck(14, 21));
console.log(valCheck(14, 20));
console.log(valCheck(16, 20));

Sample Output:

false
true
false

Flowchart:

Flowchart: JavaScript - Check from two given non-negative integers that whether one of the number is multiple of 7 or 11

ES6 Version:

function valCheck (a, b) {
if (!((a % 7 == 0 || a % 11 == 0) && (b % 7 == 0 || b % 11 == 0))) {
return ((a % 7 == 0 || a % 11 == 0) || (b % 7 == 0 || b % 11 == 0));
}
else
return false;
}
console.log(valCheck(14, 21));
console.log(valCheck(14, 20));
console.log(valCheck(16, 20));

Live Demo:

See the Pen JavaScript: Check two given non-negative integers that whether one of the number (not both) is multiple of 7 or 11. - basic-ex-46 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to check two given integer values and return true if one of the number is 15 or if their sum or difference is 15.
Next:Write a JavaScript program to check if a number in the range 40..10000 presents in two number (in same range).

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JavaScript: Tips of the Day

Promise object

const myPromise = () => Promise.resolve('I have resolved!');

function firstFunction() {
  myPromise().then(res => console.log(res));
  console.log('second');
}

async function secondFunction() {
  console.log(await myPromise());
  console.log('second');
}

firstFunction();
secondFunction();

With a promise, we basically say I want to execute this function, but I'll put it aside for now while it's running since this might take a while. Only when a certain value is resolved (or rejected), and when the call stack is empty, I want to use this value.
We can get this value with both .then and the await keyword in an async function. Although we can get a promise's value with both .then and await, they work a bit differently.
In the firstFunction, we (sort of) put the myPromise function aside while it was running, but continued running the other code, which is console.log('second') in this case. Then, the function resolved with the string I have resolved, which then got logged after it saw that the callstack was empty.
With the await keyword in secondFunction, we literally pause the execution of an async function until the value has been resolved before moving to the next line.
This means that it waited for the myPromise to resolve with the value I have resolved, and only once that happened, we moved to the next line: second got logged.

Ref: https://bit.ly/3jFRBje