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JavaScript: Rotate the elements left of a given array of integers of length 3

JavaScript Basic: Exercise-70 with Solution

Write a JavaScript program to rotate the elements left of a given array of integers of length 3.

Pictorial Presentation:

JavaScript: Rotate the elements left of a given array of integers of length 3.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>JavaScript program to rotate the elements left of a given array of integers of length 3.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function rotate_elements_left(array)
{
    return [array[1], array[2], array[0]];
}
console.log(rotate_elements_left([3, 4, 5]));  
console.log(rotate_elements_left([0, -1, 2]));  
console.log(rotate_elements_left([7, 6, 5])); 

Sample Output:

[4,5,3]
[-1,2,0]
[6,5,7]

Flowchart:

Flowchart: JavaScript - Rotate the elements left of a given array of integers of length 3

ES6 Version:

function rotate_elements_left(array)
{
    return [array[1], array[2], array[0]];
}
console.log(rotate_elements_left([3, 4, 5]));  
console.log(rotate_elements_left([0, -1, 2]));  
console.log(rotate_elements_left([7, 6, 5]));

Live Demo:

See the Pen JavaScript - Rotate the elements left of a given array of integers of length 3 - basic-ex-70 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to compute the sum of three elements of a given array of integers of length 3.
Next: Write a JavaScript program to check if 1 appears in first or last position of a given array of integers.

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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925 

Output:

385
3025
2925