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JavaScript: Find the maximum difference among all possible pairs of a given array of integers

JavaScript Basic: Exercise-93 with Solution

Write a JavaScript program to find the maximum difference among all possible pairs of a given array of integers.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>Find the maximum difference among all possible pairs of a given array of integers.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function array_max_diff(arr) {

    var max_result = 0;

    for(var i=0;i<arr.length;i++)
       {
        for(var k=0; k!=i && k<arr.length; k++)
        {
            var diff = Math.abs(arr[i]-arr[k]);
            max_result = Math.max(max_result, diff);
        }
    }
    return max_result;
}
console.log(array_max_diff([1, 2, 3, 8, 9]))
console.log(array_max_diff([1, 2, 3, 18, 9]))
console.log(array_max_diff([13, 2, 3, 8, 9]))

Sample Output:

8
17
11

Flowchart:

Flowchart: JavaScript - Find the maximum difference among all possible pairs of a given array of integers

ES6 Version:

function array_max_diff(arr) {

    let max_result = 0;

    for(let i=0;i<arr.length;i++)
       {
        for(let k=0; k!=i && k<arr.length; k++)
        {
            const diff = Math.abs(arr[i]-arr[k]);
            max_result = Math.max(max_result, diff);
        }
    }
    return max_result;
}
console.log(array_max_diff([1, 2, 3, 8, 9]))
console.log(array_max_diff([1, 2, 3, 18, 9]))
console.log(array_max_diff([13, 2, 3, 8, 9]))

Live Demo:

See the Pen javascript-basic-exercise-93 by w3resource (@w3resource) on CodePen.


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Previous: Write a JavaScript program to find the maximum difference between any two adjacent elements of a given array of integers.
Next: Write a JavaScript program to find the number which appears most in a given array of integers.

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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925 

Output:

385
3025
2925