JavaScript: Replace all the numbers with a specified number of a given array of integers
JavaScript Basic: Exercise-95 with Solution
Write a JavaScript program to replace all the numbers with a specified number of a given array of integers.
Pictorial Presentation:

Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>Replace all the numbers with a specified number of a given array of integers</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function array_element_replace(arr, old_value, new_value) {
for (var i = 0; i < arr.length; i++) {
if (arr[i] === old_value) {
arr[i] = new_value;
}
}
return arr;
}
num = [1, 2, 3, 2, 2, 8, 1, 9];
console.log("Original Array: "+num);
console.log(array_element_replace(num, 2, 5));
Sample Output:
Original Array: 1,2,3,2,2,8,1,9 [1,5,3,5,5,8,1,9]
Flowchart:

ES6 Version:
function array_element_replace(arr, old_value, new_value) {
for (let i = 0; i < arr.length; i++) {
if (arr[i] === old_value) {
arr[i] = new_value;
}
}
return arr;
}
num = [1, 2, 3, 2, 2, 8, 1, 9];
console.log(`Original Array: ${num}`);
console.log(array_element_replace(num, 2, 5));
Live Demo:
See the Pen javascript-basic-exercise-95 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to find the number which appears most in a given array of integers.
Next: Write a JavaScript program to compute the sum of absolute differences of consecutive numbers of a given array of integers.
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JavaScript: Tips of the Day
Returns the sum of the powers of all the numbers from start to end (both inclusive)
Example:
const sumPower = (end, power = 2, start = 1) => Array(end + 1 - start) .fill(0) .map((x, i) => (i + start) ** power) .reduce((a, b) => a + b, 0); console.log(sumPower(10)); // 385 console.log(sumPower(10, 3)); // 3025 console.log(sumPower(10, 3, 5)); // 2925
Output:
385 3025 2925
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