JavaScript: Iterates the integers from 1 to 100

JavaScript Conditional Statement and loops: Exercise-7 with Solution

FizzBuzz

Write a JavaScript program that iterates integers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for multiples of five print "Buzz". For numbers multiples of both three and five print "FizzBuzz".

Sample Solution:

JavaScript Code:

// Loop through numbers from 1 to 100
for (var i = 1; i <= 100; i++) {
    // Check if the number is divisible by both 3 and 5
    if (i % 3 === 0 && i % 5 === 0) {
        console.log(i + " FizzBuzz");
    }
    // Check if the number is divisible by 3
    else if (i % 3 === 0) {
        console.log(i + " Fizz");
    }
    // Check if the number is divisible by 5
    else if (i % 5 === 0) {
        console.log(i + " Buzz");
    }
    // If none of the above conditions are met, print the number
    else {
        console.log(i);
    }
} 

Output:

1
2
3 Fizz
4
5 Buzz
6 Fizz
7
8
9 Fizz
10 Buzz
-----

Flowchart:

Live Demo:

See the Pen javascript-conditional-statements-and-loops-exercise-7 by w3resource (@w3resource) on CodePen.

For more Practice: Solve these Related Problems:

• Write a JavaScript function that implements FizzBuzz for numbers 1 to 100 using nested ternary operators.
• Write a JavaScript function that generates an array of FizzBuzz outputs for numbers 1 to 100 and returns it.
• Write a JavaScript function that implements FizzBuzz recursively for numbers 1 to 100.
• Write a JavaScript function that outputs FizzBuzz results for 1 to 100 without using any conditional statements.

Go to:

• JavaScript conditional statements and loops Exercises Home ↩
• JavaScript Exercises Home ↩

PREV : Student Grades Calculation.
NEXT : Happy Numbers (First 5).

Improve this sample solution and post your code through Disqus.