JavaScript: Find the armstrong numbers of 3 digits
JavaScript Conditional Statement and loops: Exercise-9 with Solution
Write a JavaScript program to find the armstrong numbers of 3 digits.
Note : An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371.
Pictorial Presentation:

Sample Solution:-
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset=utf-8 />
<title>Three digit armstrong numbers</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function three_digit_armstrong_number()
{
for (var i = 1; i < 10; ++i)
{
for (var j = 0; j < 10; ++j)
{
for (var k = 0; k < 10; ++k)
{
var pow = (Math.pow(i,3) + Math.pow(j,3) + Math.pow(k,3));
var plus = (i * 100 + j * 10 + k);
if (pow == plus)
{
console.log(pow);
}
}
}
}
}
three_digit_armstrong_number();
Sample Output:
153 370 371 407
Flowchart:

Live Demo:
See the Pen javascript-conditional-statements-and-loops-exercise-9 by w3resource (@w3resource) on CodePen.
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JavaScript: Tips of the Day
Creates an array of elements, ungrouping the elements in an array produced by zip and applying the provided function
Example:
const tips_unzip = (arr, fn) => arr .reduce( (acc, val) => (val.forEach((v, i) => acc[i].push(v)), acc), Array.from({ length: Math.max(...arr.map(x => x.length)) }).map(x => []) ) .map(val => fn(...val)); console.log(tips_unzip([[2, 15, 200], [3, 25, 300]], (...args) => args.reduce((acc, v) => acc + v, 0)));
Output:
[5, 40, 500]
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