JavaScript: Find the armstrong numbers of 3 digits

JavaScript Conditional Statement and loops: Exercise-9 with Solution

Write a JavaScript program to find the Armstrong numbers of 3 digits.

Note : An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371.

Visual Presentation:

Sample Solution:-

JavaScript Code:

``````// Function to find and print three-digit Armstrong numbers
function three_digit_armstrong_number() {
for (var i = 1; i < 10; ++i) {
for (var j = 0; j < 10; ++j) {
for (var k = 0; k < 10; ++k) {
// Calculate the cube of each digit and sum them
var pow = Math.pow(i, 3) + Math.pow(j, 3) + Math.pow(k, 3);
// Calculate the number formed by the digits
var plus = i * 100 + j * 10 + k;

// Check if the sum of cubes is equal to the number
if (pow === plus) {
console.log(pow);
}
}
}
}
}

// Call the function to find three-digit Armstrong numbers
three_digit_armstrong_number();
```
```

Sample Output:

```153
370
371
407
```

Flowchart:

Live Demo:

See the Pen javascript-conditional-statements-and-loops-exercise-9 by w3resource (@w3resource) on CodePen.

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