# JavaScript: Least number of perfect square that sums upto n

## JavaScript Math: Exercise-106 with Solution

Write a JavaScript program that accepts an integer (n) as input and calculates the lowest number of exact square numbers that sum to n.

In mathematics, a square number or perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, 9 is a square number, since it equals 32 and can be written as 3 × 3.

Example:

Input: 12

Output: 3

Explanation: 12 = 3^{2} + 1^{2} + 1^{2}

Input: 63

Output: 4

Explanation: 63 = 7^{2} + 3^{2} + 2^{2} + 1^{2}.

**Test Data:**

(12) -> 3

(13) -> 2

(63) -> 4

**Sample Solution:**

**HTML Code:**

```
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript program to Least number of perfect square that sums upto n</title>
</head>
<body>
</body>
</html>
```

**JavaScript Code:**

```
function test(n) {
var maps = []
maps[0] = 0
maps[1] = 1
maps[2] = 2
maps[3] = 3
for (var i = 3; i <= n; i++) {
maps[i] = maps[i-1] + 1
for (var j = 1; j*j <= i; j++) {
maps[i] = Math.min(maps[i], maps[i-j*j] + 1)
}
}
return maps[n]
}
n = 12
console.log("Number n = " +n)
console.log("Least number of perfect square that sums upto n: "+test(n));
n = 13
console.log("Number n = " +n)
console.log("Least number of perfect square that sums upto n: "+test(n));
n = 63
console.log("Number n = " +n)
console.log("Least number of perfect square that sums upto n: "+test(n));
```

Sample Output:

Number n = 12 Least number of perfect square that sums upto n: 3 Number n = 13 Least number of perfect square that sums upto n: 2 Number n = 63 Least number of perfect square that sums upto n: 4

**Flowchart: **

**Live Demo: **

See the Pen javascript-math-exercise-106 by w3resource (@w3resource) on CodePen.

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