JavaScript: Swap three numbers
JavaScript Math: Exercise-75 with Solution
Write a JavaScript program to swap three numbers without a third variable.
Test Data:
(100, 200, 300) -> 300, 100, 200
Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript program to Swap three numbers</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function test(x, y, z)
{
x = x + y + z;
y = x - (y + z);
z = x - (y + z);
x = x - (y + z);
return [x, y, z];
}
x = 100;
y = 200;
z = 300;
console.log("Before swapping:")
console.log("x = "+x);
console.log("y = "+y);
console.log("z = "+z);
result = test(x, y, z);
console.log("After swapping:");
console.log("x = "+result[0]);
console.log("y = "+result[1]);
console.log("z = "+result[2]);
Sample Output:
Before swapping: x = 100 y = 200 z = 300 After swapping: x = 300 y = 100 z = 200
Flowchart:

Live Demo:
See the Pen javascript-math-exercise-75 by w3resource (@w3resource) on CodePen.
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Next: Subtract without arithmetic operators.
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