JavaScript: Sum of oddly divisible numbers from a range

JavaScript Math: Exercise-89 with Solution

Write a JavaScript program that takes three arguments x, y, n and calculates the sum of the numbers oddly divided by n from the range x, y inclusive.

Test Data:
(1,5,3) -> 3
(100, 1000, 5) -> 99550

Sample Solution:

JavaScript Code:

/**
 * Function to calculate the sum of numbers divisible by a given number within a specified range.
 * @param {number} x - The starting value of the range.
 * @param {number} y - The ending value of the range.
 * @param {number} n - The divisor to check divisibility.
 * @returns {number} - The sum of numbers divisible by 'n' within the range from 'x' to 'y'.
 */
function test(x, y, n) {
    // Initialize the sum of divisible numbers
    let num_sum = 0;
    // Loop through each number within the specified range
    for (let i = x; i <= y; i++) {
        // If the current number is divisible by 'n', add it to the sum; otherwise, add 0
        num_sum += i % n === 0 ? i : 0;
    }
    // Return the sum of divisible numbers
    return num_sum;
}

// Test cases
// Define the range and divisor for the first test case
x = 1;
y = 5;
n = 3;
// Print range and divisor information
console.log("Range: " + x + "-" + y);
console.log("Divisible number: " + n);
// Calculate and print the sum of oddly divisible numbers within the specified range
console.log("Sum of oddly divisible numbers from the said range: " + test(x, y, n));

// Repeat the above steps for a different range and divisor
x = 100;
y = 1000;
n = 5;
console.log("Range: " + x + "-" + y);
console.log("Divisible number: " + n);
console.log("Sum of oddly divisible numbers from the said range: " + test(x, y, n));

Output:

Range: 1-5
Divisible number: 3
Sum of oddly divisible numbers from a the said range: 3
Range: 100-1000
Divisible number: 5
Sum of oddly divisible numbers from a the said range: 99550

Flowchart:

Live Demo:

See the Pen javascript-math-exercise-89 by w3resource (@w3resource) on CodePen.

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