JavaScript: Binary Search Algorithm using recursion

Last update on April 22 2023 12:19:20 (UTC/GMT +8 hours)

JavaScript Function: Exercise-12 with Solution

Write a JavaScript program to search for a given integer in an array of sorted integers using the Binary Search Algorithm and recursion.

Test Data:
([1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 17, 19, 20, 22, 23], 6) -> 4
([1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 17, 19, 20, 22, 23], 16) -> -1

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>Binary Search Algorithm using recursion</title>
</head>
<body>

</body>
</html>

JavaScript Code:

/**
 * Source: bit.ly/3h77zX6
 * @function BinarySearch
 * @description Search the integer inside the sorted integers array using Binary Search Algorithm.
 * @param {Integer[]} arr - sorted array of integers
 * @param {Integer} low - The input integer
 * @param {Integer} high - The input integer
 * @param {Integer} searchValue - The input integer
 * @return {Integer} - return index of searchValue if found else return -1.
  */
const binary_Search = (arr, searchValue, low = 0, high = arr.length - 1) => {
  // base case
  if (high < low || arr.length === 0) return -1
  const mid = low + Math.floor((high - low) / 2)
  // If the element is present at the middle
  if (arr[mid] === searchValue) {
    return mid
  }
  // If element is smaller than mid, then
  // it can only be present in left subarray
  if (arr[mid] > searchValue) {
    return binary_Search(arr, searchValue, low, mid - 1)
  }
  // Else the element can only be present in right subarray
  return binary_Search(arr, searchValue, mid + 1, high)
}
 const myArray = [1, 2, 3, 5, 6, 7, 10, 11, 14, 15, 17, 19, 20, 22, 23];
 console.log(binary_Search(myArray, 6));
 console.log(binary_Search(myArray, 16));

Output:

4
-1

Flowchart:

Flowchart: JavaScript recursion function- Binary Search Algorithm using recursion.

Live Demo:

See the Pen javascript-recursion-function-exercise-12 by w3resource (@w3resource) on CodePen.

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