Kotlin Program: Count even and odd elements in an array

Kotlin Control Flow: Exercise-9 with Solution

Write a Kotlin program to count the number of even and odd elements in an array.

Sample Solution:

Kotlin Code:

fun main() {
    val numbers = arrayOf(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

    val evenCount = countEvenNumbers(numbers)
    val oddCount = countOddNumbers(numbers)

    println("Number of even elements: $evenCount")
    println("Number of odd elements: $oddCount")
}

fun countEvenNumbers(numbers: Array): Int {
    var count = 0

    for (number in numbers) {
        if (number % 2 == 0) {
            count++
        }
    }

    return count
}

fun countOddNumbers(numbers: Array): Int {
    var count = 0

    for (number in numbers) {
        if (number % 2 != 0) {
            count++
        }
    }

    return count
}

Sample Output:

Number of even elements: 6
Number of odd elements: 6

Explanation:

The "numbers" array contains the elements for which we want to count even and odd numbers.

• The "countEvenNumbers()" function takes the numbers array as an argument and counts the number of even elements in the array.
• Inside the "countEvenNumbers()" function, we initialize a variable count to hold the count of even numbers and set it to 0.
• We use a for loop to iterate over each element in the numbers array.
• For each element, we check if it is divisible by 2 (i.e., even) by using the condition number % 2 == 0. If it is, we increment the count variable.
• After iterating through all the elements, we return the final count of even numbers.
• The "countOddNumbers()" function is similar to countEvenNumbers(), but it counts odd elements instead.
• In the main() function, we call "countEvenNumbers()" and "countOddNumbers()" with the numbers array and store the respective counts in evenCount and oddCount.
• Finally, we print the counts of even and odd elements using println() function.

Kotlin Editor:

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