MongoDB Exercise - Find the average score for each restaurant
Write a MongoDB query to find the average score for each restaurant.
Structure of 'restaurants' collection :
{
"address": {
"building": "1007",
"coord": [ -73.856077, 40.848447 ],
"street": "Morris Park Ave",
"zipcode": "10462"
},
"borough": "Bronx",
"cuisine": "Bakery",
"grades": [
{ "date": { "$date": 1393804800000 }, "grade": "A", "score": 2 },
{ "date": { "$date": 1378857600000 }, "grade": "A", "score": 6 },
{ "date": { "$date": 1358985600000 }, "grade": "A", "score": 10 },
{ "date": { "$date": 1322006400000 }, "grade": "A", "score": 9 },
{ "date": { "$date": 1299715200000 }, "grade": "B", "score": 14 }
],
"name": "Morris Park Bake Shop",
"restaurant_id": "30075445"
}
Query:
db.restaurants.aggregate([{
$unwind: "$grades"
},
{
$group: {
_id: "$name",
avgScore: {
$avg: "$grades.score"
}
}
}
])
Output:
{ _id: "Buddy'S Burrito & Taco Bar", avgScore: 13.333333333333334 },
{ _id: 'Bergen Beach Cafe', avgScore: 12 },
{ _id: 'Pergola Des Artistes', avgScore: 6.333333333333333 },
{ _id: 'ZumStammtisch', avgScore: 12.833333333333334 },
{ _id: 'Shubert Theater', avgScore: 10.4 },
{ _id: "Big Daddy'S Diner", avgScore: 13.8 },
{ _id: 'Strokos Gourmet Deli', avgScore: 12.8 },
{ _id: 'Azusa Of Japan', avgScore: 11 },
{ _id: 'Pax Wholesome Foods', avgScore: 6.875 },
{ _id: "Erin'S Isle", avgScore: 9.5 },
.....
Explanation:
The said query in MongoDB makes an array of documents, representing a restaurant and its average score. The _id field of each document will contain the name of the restaurant, and the avgScore field will contain the calculated average score.
The $unwind stage is used to "unwind" an array field grades in the restaurants collection. As a result, a separate document will be created for each grade in the restaurants collection.
The $group stage groups the documents by the name field and calculates the average score of all the grades for each restaurant using the $avg operator.
Note: This output is generated using MongoDB server version 3.6
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