MongoDB Exercise - Each borough's top 5 restaurants with the most "A" grades
Write a MongoDB query to find the top 5 restaurants in each borough with the highest number of "A" grades.
Structure of 'restaurants' collection :
{ "address": { "building": "1007", "coord": [ -73.856077, 40.848447 ], "street": "Morris Park Ave", "zipcode": "10462" }, "borough": "Bronx", "cuisine": "Bakery", "grades": [ { "date": { "$date": 1393804800000 }, "grade": "A", "score": 2 }, { "date": { "$date": 1378857600000 }, "grade": "A", "score": 6 }, { "date": { "$date": 1358985600000 }, "grade": "A", "score": 10 }, { "date": { "$date": 1322006400000 }, "grade": "A", "score": 9 }, { "date": { "$date": 1299715200000 }, "grade": "B", "score": 14 } ], "name": "Morris Park Bake Shop", "restaurant_id": "30075445" }
Query:
db.restaurants.aggregate([
{$unwind: "$grades"},
{$match: {"grades.grade": "A"}},
{$group: {
_id: {borough: "$borough", restaurant_id: "$restaurant_id"},
gradeCount: {$sum: 1}
}},
{$sort: {
"_id.borough": 1,
gradeCount: -1
}},
{$group: {
_id: "$_id.borough",
topRestaurants: {$push: {restaurant_id: "$_id.restaurant_id", gradeCount: "$gradeCount"}}
}},
{$project: {
_id: 0,
borough: "$_id",
topRestaurants: {$slice: ["$topRestaurants", 5]}
}}
])
Output:
{ borough: 'Bronx', topRestaurants: [ { restaurant_id: '40863575', gradeCount: 7 }, { restaurant_id: '40369087', gradeCount: 7 }, { restaurant_id: '40399778', gradeCount: 7 }, { restaurant_id: '40738028', gradeCount: 6 }, { restaurant_id: '40607093', gradeCount: 6 } ] }, { borough: 'Manhattan', topRestaurants: [ { restaurant_id: '40752011', gradeCount: 7 }, { restaurant_id: '40798457', gradeCount: 7 }, { restaurant_id: '40873102', gradeCount: 7 }, { restaurant_id: '40401093', gradeCount: 7 }, { restaurant_id: '40735660', gradeCount: 7 } ] }, { borough: 'Queens', topRestaurants: [ { restaurant_id: '40362432', gradeCount: 7 }, { restaurant_id: '40816235', gradeCount: 7 }, { restaurant_id: '40787054', gradeCount: 7 }, { restaurant_id: '40393093', gradeCount: 7 }, { restaurant_id: '40786301', gradeCount: 7 } ] }, .....
Explanation:
The said query in MongoDB that finds the top 5 restaurants in each borough with the highest number of "A" grades.
The $unwind stage creates a separate document for each element in the grades array.
The $match stage filters the documents with grades that have a grade value of "A".
The $group operator groups the documents by borough and restaurant_id, and count the number of grades using the $sum aggregation operator.
The _id field in the $group stage is a composite key that consists of the borough and restaurant_id fields.
The $sort stage sorts the documents by borough and grade count in descending order.
The $group stage again groups the documents by borough and create an array of the top 5 restaurants for each borough using the $push aggregation operator.
The $slice operator is used to limit the size of the topRestaurants array to 5.
Note: This output is generated using MongoDB server version 3.6
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Previous: Find the top 5 restaurants for each cuisine type, along with their average score.
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https://www.w3resource.com/mongodb-exercises/mongodb-exercise-86.php
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