w3resource

Basic SELECT statement: Get unique department ID from employee table

MySQL Basic Select Statement: Exercise-2 with Solution

Write a query to get unique department ID from employee table.

Sample table: employees

+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
| EMPLOYEE_ID | FIRST_NAME  | LAST_NAME   | EMAIL    | PHONE_NUMBER       | HIRE_DATE  | JOB_ID     | SALARY   | COMMISSION_PCT | MANAGER_ID | DEPARTMENT_ID |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+
|         100 | Steven      | King        | SKING    | 515.123.4567       | 1987-06-17 | AD_PRES    | 24000.00 |           0.00 |          0 |   		  90 |
|         101 | Neena       | Kochhar     | NKOCHHAR | 515.123.4568       | 1987-06-18 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         102 | Lex         | De Haan     | LDEHAAN  | 515.123.4569       | 1987-06-19 | AD_VP      | 17000.00 |           0.00 |        100 |            90 |
|         103 | Alexander   | Hunold      | AHUNOLD  | 590.423.4567       | 1987-06-20 | IT_PROG    |  9000.00 |           0.00 |        102 |            60 |
|         104 | Bruce       | Ernst       | BERNST   | 590.423.4568       | 1987-06-21 | IT_PROG    |  6000.00 |           0.00 |        103 |            60 |
|         105 | David       | Austin      | DAUSTIN  | 590.423.4569       | 1987-06-22 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         106 | Valli       | Pataballa   | VPATABAL | 590.423.4560       | 1987-06-23 | IT_PROG    |  4800.00 |           0.00 |        103 |            60 |
|         107 | Diana       | Lorentz     | DLORENTZ | 590.423.5567       | 1987-06-24 | IT_PROG    |  4200.00 |           0.00 |        103 |            60 |
|         108 | Nancy       | Greenberg   | NGREENBE | 515.124.4569       | 1987-06-25 | FI_MGR     | 12000.00 |           0.00 |        101 |           100 |
.........
|         206 | William     | Gietz       | WGIETZ   | 515.123.8181       | 1987-10-01 | AC_ACCOUNT |  8300.00 |           0.00 |        205 |           110 |
+-------------+-------------+-------------+----------+--------------------+------------+------------+----------+----------------+------------+---------------+

View the table

Code:

-- Selecting distinct values from the department_id column
SELECT DISTINCT department_id
-- Selecting data from the employees table
FROM employees;

Explanation:

  • This SQL query selects data from the employees table.
  • It retrieves distinct values from the department_id column.
  • The DISTINCT keyword ensures that only unique values of department_id are returned, eliminating duplicates.
  • This query is useful when you want to get a list of all unique department IDs present in the employees table.

Relational Algebra Expression:

Relational Algebra Expression: Basic SELECT statement: Get unique department ID from employee table.


Relational Algebra Tree:

Relational Algebra Tree: Basic SELECT statement: Get unique department ID from employee table.


Pictorial Presentation of the above query

Pictorial Presentation: Query to get unique department ID from employee table.


Result :

Result: Get unique department ID from employee table.


Go to:


PREV : Write a query to display the names (first_name, last_name) using alias name "First Name", "Last Name".
NEXT : Write a query to get the details of all employees according to first name in descending order.

MySQL Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

What is the difficulty level of this exercise?



Follow us on Facebook and Twitter for latest update.