MySQL Subquery Exercises: Find the name and salary of the employees whose salary is greater than the average salary
MySQL Subquery: Exercise-5 with Solution
Write a MySQL query to find the name (first_name, last_name), and salary of the employees whose salary is greater than the average salary.
Sample table: employees
Code:
-- Selecting the first name, last name, and salary of employees
SELECT first_name, last_name, salary
-- Selecting data from the employees table
FROM employees
-- Filtering the result set to include only employees whose salary is greater than the average salary of all employees
WHERE salary >
-- Subquery to calculate the average salary from the employees table
(SELECT AVG(salary) FROM employees);
Explanation:
- This MySQL code selects the first name, last name, and salary of employees from a table named "employees".
- It filters the results to only include employees whose salary is greater than the average salary of all employees.
- This is achieved by using a subquery to calculate the average salary from the "employees" table, and then comparing each employee's salary with this average salary in the outer query.
MySQL Subquery Syntax:
- The subquery (inner query) executes once before the main query (outer query) executes.
- The main query (outer query) use the subquery result.
MySQL AVG() function returns the average value of a set of values or an expression.
MySQL Code Editor:
Structure of 'hr' database :
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous:Write a query to find the name (first_name, last_name) of the employees who are managers.
Next:Write a MySQL query to find the name (first_name, last_name), and salary of the employees whose salary is equal to the minimum salary for their job grade.
What is the difficulty level of this exercise?
- Weekly Trends and Language Statistics
- Weekly Trends and Language Statistics