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PHP Date Exercises : Add/subtract the number of days from a particular date

PHP date: Exercise-16 with Solution

Write a PHP script to add/subtract the number of days from a particular date.

Sample Solution:

PHP Code:

<?php
$dt='2011-01-01';
echo 'Original date : '.$dt."\n";
$no_days = 40;
$bdate = strtotime("-".$no_days." days", strtotime($dt));
$adate = strtotime("+".$no_days." days", strtotime($dt));
echo 'Before 40 days : '.date("Y-m-d", $bdate)."\n";
echo 'After  40 days : '.date("Y-m-d", $adate)."\n";
?>

Sample Output:

Original date : 2011-01-01                                  
Before 40 days : 2010-11-22                                 
After  40 days : 2011-02-10

Flowchart :

Flowchart: Add/subtract the number of days from a particular date

PHP Code Editor:

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Previous: Write a PHP script to check if a date is a weekend or not.
Next: Write a PHP function to get start and end date of a week (by week number) of a particular year.

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PHP: Tips of the Day

SQL injection that gets around mysql_real_escape_string()

Consider the following query:

$iId = mysql_real_escape_string("1 OR 1=1");    
$sSql = "SELECT * FROM table WHERE id = $iId";

mysql_real_escape_string() will not protect you against this. The fact that you use single quotes (' ') around your variables inside your query is what protects you against this. The following is also an option:

$iId = (int)"1 OR 1=1";
$sSql = "SELECT * FROM table WHERE id = $iId";

Ref : https://bit.ly/32q3bJ7