PostgreSQL Aggregate Functions and Group By: Find the manager ID and the salary of the lowest-paid employee under that manager
9. Write a query to find the manager ID and the salary of the lowest-paid employee under that manager.
Sample Solution:
Code:
SELECT manager_id, MIN(salary)
FROM employees
WHERE manager_id IS NOT NULL
GROUP BY manager_id
ORDER BY MIN(salary) DESC;
Sample table: employees
Output:
pg_exercises=# SELECT manager_id, MIN(salary) pg_exercises-# FROM employees pg_exercises-# WHERE manager_id IS NOT NULL pg_exercises-# GROUP BY manager_id pg_exercises-# ORDER BY MIN(salary) DESC; manager_id | min ------------+---------- 0 | 24030.00 102 | 9030.00 205 | 8330.00 145 | 7030.00 146 | 7030.00 108 | 6930.00 147 | 6230.00 149 | 6230.00 148 | 6130.00 201 | 6030.00 100 | 5830.00 101 | 4430.00 103 | 4230.00 123 | 2530.00 124 | 2530.00 114 | 2530.00 120 | 2230.00 122 | 2230.00 121 | 2130.00 (19 rows)
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