w3resource

PostgreSQL JOINS: Make a join with tables employees and departments to get the department name and number of employees working in each department


6. Write a query to make a join with two tables employees and departments to get the department name and number of employees working in each department.

Sample Solution:

Code:

-- This SQL query retrieves the department name along with the count of employees in each department, ordered alphabetically by department name.

SELECT department_name AS "Department Name", -- Selects the department_name column and labels it as "Department Name"
COUNT(*) AS "No of Employees" -- Calculates the count of employees in each department and labels it as "No of Employees"
FROM departments -- Specifies the first table from which to retrieve data, in this case, the departments table
INNER JOIN employees -- Performs an inner join between the departments and employees tables
ON employees.department_id = departments.department_id -- Specifies the join condition based on the department_id column
GROUP BY departments.department_id, department_name -- Groups the results by department_id and department_name
ORDER BY department_name; -- Orders the results alphabetically by department_name

Explanation:

  • This SQL query retrieves the department name along with the count of employees in each department, ordered alphabetically by department name.
  • The SELECT statement selects the department_name column from the departments table and calculates the count of employees in each department, labeling them as "Department Name" and "No of Employees" respectively.
  • The FROM clause specifies the first table from which to retrieve data, which is the departments table.
  • An INNER JOIN operation is performed between the departments and employees tables based on the common column department_id.
  • The ON clause specifies the join condition where the department_id in the employees table matches the department_id in the departments table.
  • The GROUP BY clause groups the results by department_id and department_name.
  • The ORDER BY clause orders the results alphabetically by department_name.

Sample table: employees


Sample table: departments


Output:

pg_exercises=# SELECT department_name AS "Department Name",
pg_exercises-# COUNT(*) AS "No of Employees"
pg_exercises-# FROM departments
pg_exercises-# INNER JOIN employees
pg_exercises-# ON employees.department_id = departments.department_id
pg_exercises-# GROUP BY departments.department_id, department_name
pg_exercises-# ORDER BY department_name;

 Department Name  | No of Employees
------------------+-----------------
 Accounting       |               2
 Administration   |               1
 Executive        |               3
 Finance          |               6
 Human Resources  |               1
 IT               |               5
 Marketing        |               2
 Public Relations |               1
 Purchasing       |               6
 Sales            |              33
 Shipping         |              45
(11 rows)

Practice Online


Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a query to make a join with a table employees and itself to find the name, including first_name and last_name and hire date for those employees who were hired after the employee Jones.
Next: Write a query to make a join to find the employee ID, job title and number of days an employee worked, for all the employees who worked in a department which ID is 90.

What is the difficulty level of this exercise?



Become a Patron!

Follow us on Facebook and Twitter for latest update.

It will be nice if you may share this link in any developer community or anywhere else, from where other developers may find this content. Thanks.

https://www.w3resource.com/postgresql-exercises/join/postgresql-join-exercise-6.php