Python BeautifulSoup: Retrieve children of the html tag from a given web page

BeautifulSoup: Exercise-14 with Solution

Write a Python program to retrieve children of the html tag from a given web page.

Sample Solution:

Python Code:

import requests
from bs4 import BeautifulSoup
url = 'https://www.python.org/'
reqs = requests.get(url)
soup = BeautifulSoup(reqs.text, 'lxml')
print("\nChildren of the html tag (https://www.python.org):\n")
root = soup.html    
root_childs = [e.name for e in root.children if e.name is not None]

Sample Output:

Children of the html tag (https://www.python.org):

['head', 'body']

Python Code Editor:

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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP