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Python BeautifulSoup: Print the element(s) that has a specified id of a given web page

BeautifulSoup: Exercise-19 with Solution

Write a Python program to print the element(s) that has a specified id of a given web page.

Sample Solution:

Python Code:

import requests
import re
from bs4 import BeautifulSoup
url = 'https://www.python.org/'
reqs = requests.get(url)
soup = BeautifulSoup(reqs.text, 'lxml')
print("\nelement(s) that has #python-network id:\n")
print(soup.select_one("#python-network"))

Sample Output:

element(s) that has #python-network id:

<a aria-hidden="true" class="jump-link" href="#top" id="python-network">
<span aria-hidden="true" class="icon-arrow-up"><span>▲</span></span> The Python Network
</a>

Python Code Editor:

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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP