﻿ Python: Create a coded string from a given string, using specified formula - w3resource

# Python: Create a coded string from a given string, using specified formula

## Python Basic - 1: Exercise-121 with Solution

Write a Python program to create a coded string from a given string, using specified formula.

Replace all 'P' with '9', 'T' with '0', 'S' with '1', 'H' with '6' and 'A' with '8'

Sample Solution-1:

Python Code:

``````def test(str):
return str.translate(str.maketrans('PTSHA', '90168'))
str = "PHP"
print("Original string: ",str)
print("Coded string: ",test(str))
str = "JAVASCRIPT"
print("\nOriginal string: ",str)
print("Coded string: ",test(str))
``````

Sample Output:

```Original string:  PHP
Coded string:  969

Original string:  JAVASCRIPT
Coded string:  J8V81CRI90
```

Flowchart:

Sample Solution-2:

Python Code:

``````def test(str):
return str.replace('P', '9').replace('T', '0').replace('S', '1').replace('H', '6').replace('A', '8')

str = "PHP"
print("Original string: ",str)
print("Coded string: ",test(str))
str = "JAVASCRIPT"
print("\nOriginal string: ",str)
print("Coded string: ",test(str))
``````

Sample Output:

```Original string:  PHP
Coded string:  969

Original string:  JAVASCRIPT
Coded string:  J8V81CRI90
```

Flowchart:

Python Code Editor:

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## Python: Tips of the Day

How to make a flat list out of list of lists?

Given a list of lists l

```flat_list = [item for sublist in l for item in sublist]
```

which means:

```flat_list = []
for sublist in l:
for item in sublist:
flat_list.append(item)
```

is faster than the shortcuts posted so far. (l is the list to flatten.) Here is the corresponding function:

flatten = lambda l: [item for sublist in l for item in sublist]

As evidence, you can use the timeit module in the standard library:

```\$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' '[item for sublist in l for item in sublist]'
10000 loops, best of 3: 143 usec per loop
\$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'sum(l, [])'
1000 loops, best of 3: 969 usec per loop
\$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'reduce(lambda x,y: x+y,l)'
1000 loops, best of 3: 1.1 msec per loop
```

Explanation: the shortcuts based on + (including the implied use in sum) are, of necessity, O(L**2) when there are L sublists -- as the intermediate result list keeps getting longer, at each step a new intermediate result list object gets allocated, and all the items in the previous intermediate result must be copied over (as well as a few new ones added at the end). So, for simplicity and without actual loss of generality, say you have L sublists of I items each: the first I items are copied back and forth L-1 times, the second I items L-2 times, and so on; total number of copies is I times the sum of x for x from 1 to L excluded, i.e., I * (L**2)/2.

The list comprehension just generates one list, once, and copies each item over (from its original place of residence to the result list) also exactly once.

Ref: https://bit.ly/3dKsNTR