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Python: Print Emojis using unicode Characters or CLDR (Common Locale Data Repository ) short names

Python Basic - 1: Exercise-143 with Solution

Write a Python program to print Emojis using unicode characters or CLDR (Common Locale Data Repository ) short names.

Note: The Common Locale Data Repository Project, often abbreviated as CLDR, is a project of the Unicode Consortium to provide locale data in XML format for use in computer applications. CLDR contains locale-specific information that an operating system will typically provide to applications.

Using Unicode characters:

Sample Solution-1:

Python Code:

print("Smiling face with heart-eyes:")
print("\U0001F60D")
print("Unamused face:")
print("\U0001F612")
print("Beaming face with smiling eyes:")
print("\U0001F601")
print("Grinning face with sweat:")
print("\U0001F605")
print("Face with tears of joy:")
print("\U0001F602")
print("Slightly smiling face:")
print("\U0001F642")
print("Smiling face with halo:")
print("\U0001F607")
print("Zipper-mouth face:")
print("\U0001F910")
print("Grinning face:")
print("\U0001F600")
print("Rolling on the floor laughing:")
print("\U0001F923")

Sample Output:


Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Using CLDR Short Names:

Sample Solution-2:

Python Code:

print("Rolling on the floor laughing:")
print("\N{rolling on the floor laughing}")
print("Smiling face with halo:")
print("\N{smiling face with halo}")
print("Unamused face:")
print("\N{unamused face}")
print("Grinning face:")
print("\N{grinning face}")
print("Loudly crying face:")
print("\N{loudly crying face}")
print("Face with tears of joy:")
print("\N{face with tears of joy}")
print("Slightly smiling face:")
print("\N{slightly smiling face}")
print("Angry face:")
print("\N{angry face}")
print("Zipper-mouth face:")
print("\N{zipper-mouth face}")
print("Smiling face with sunglasses:")
print("\N{smiling face with sunglasses}")

Sample Output:


Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Python Code Editor:

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Previous: Write a Python program to check if every consecutive sequence of zeroes is followed by a consecutive sequence of ones of same length in a given string. Return True/False.
Next: Write a Python program to convert integer to string.

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Python: Tips of the Day

How to make a flat list out of list of lists?

Given a list of lists l

flat_list = [item for sublist in l for item in sublist]

which means:

flat_list = []
for sublist in l:
    for item in sublist:
        flat_list.append(item)

is faster than the shortcuts posted so far. (l is the list to flatten.) Here is the corresponding function:

flatten = lambda l: [item for sublist in l for item in sublist]

As evidence, you can use the timeit module in the standard library:

$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' '[item for sublist in l for item in sublist]'
10000 loops, best of 3: 143 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'sum(l, [])'
1000 loops, best of 3: 969 usec per loop
$ python -mtimeit -s'l=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'reduce(lambda x,y: x+y,l)'
1000 loops, best of 3: 1.1 msec per loop

Explanation: the shortcuts based on + (including the implied use in sum) are, of necessity, O(L**2) when there are L sublists -- as the intermediate result list keeps getting longer, at each step a new intermediate result list object gets allocated, and all the items in the previous intermediate result must be copied over (as well as a few new ones added at the end). So, for simplicity and without actual loss of generality, say you have L sublists of I items each: the first I items are copied back and forth L-1 times, the second I items L-2 times, and so on; total number of copies is I times the sum of x for x from 1 to L excluded, i.e., I * (L**2)/2.

The list comprehension just generates one list, once, and copies each item over (from its original place of residence to the result list) also exactly once.

Ref: https://bit.ly/3dKsNTR