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Python: Check whether the sum of any two numbers from the list is equal to k or not

Python Basic - 1: Exercise-64 with Solution

Given a list of numbers and a number k, write a Python program to check whether the sum of any two numbers from the list is equal to k or not.
For example, given [1, 5, 11, 5] and k = 16, return true since 11 + 5 is 16.

Sample Solution:

Python Code:

def check_sum(nums, k):   
    for i in range(len(nums)):
        for j in range(i+1, len(nums)):
            if nums[i] + nums[j] == k:
                return True
    return False
print(check_sum([12, 5, 0, 5], 10))
print(check_sum([20, 20, 4, 5], 40))
print(check_sum([1, -1], 0))
print(check_sum([1, 1, 0], 0))

Sample Output:

True
True
True
False

Pictorial Presentation:

Python: Check whether the sum of any two numbers from the list is equal to k or not
Python: Check whether the sum of any two numbers from the list is equal to k or not

Flowchart:

Flowchart: Python - Check whether the sum of any two numbers from the list is equal to k or not

Python Code Editor:

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Python: Tips of the Day

Iterating over dictionaries using 'for' loops:

I am a bit puzzled by the following code: d = {'x': 1, 'y': 2, 'z': 3} for key in d: print key, 'corresponds to', d[key] What I don't understand is the key portion. How does Python recognize ...

key is just a variable name.

for key in d:

For Python 3.x:

for key, value in d.items():

For Python 2.x:

for key, value in d.iteritems():

To test for yourself, change the word key to poop.

In Python 3.x, iteritems() was replaced with simply items(), which returns a set-like view backed by the dict, like iteritems() but even better. This is also available in 2.7 as viewitems().

The operation items() will work for both 2 and 3, but in 2 it will return a list of the dictionary's (key, value) pairs, which will not reflect changes to the dict that happen after the items() call. If you want the 2.x behavior in 3.x, you can call list(d.items()).

Ref: https://bit.ly/37dm0Qo