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Python: Test whether a given number is symmetrical or not

Python Basic - 1: Exercise-83 with Solution

Write a Python program to test whether a given number is symmetrical or not.
A number is symmetrical when it is equal of its reverse.

For example- 121 is the symmetric number.

Sample Solution:

Python Code:

def is_symmetrical_num(n):
  return str(n) == str(n)[::-1]
print(is_symmetrical_num(121))
print(is_symmetrical_num(0))
print(is_symmetrical_num(122))
print(is_symmetrical_num(990099))

Sample Output:

True
True
False
True

Pictorial Presentation:

Python: Test whether a given number is symmetrical or not.
Python: Test whether a given number is symmetrical or not.

Flowchart:

Flowchart: Python - Test whether a given number is symmetrical or not.

Python Code Editor:

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Previous: Write a Python program to calculate the median from a list of numbers.
Next: Write a Python program that accepts a list of numbers. Count the negative numbers and compute the sum of the positive numbers of the said list. Return these values through a list.

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Python: Tips of the Day

Iterating over dictionaries using 'for' loops:

I am a bit puzzled by the following code: d = {'x': 1, 'y': 2, 'z': 3} for key in d: print key, 'corresponds to', d[key] What I don't understand is the key portion. How does Python recognize ...

key is just a variable name.

for key in d:

For Python 3.x:

for key, value in d.items():

For Python 2.x:

for key, value in d.iteritems():

To test for yourself, change the word key to poop.

In Python 3.x, iteritems() was replaced with simply items(), which returns a set-like view backed by the dict, like iteritems() but even better. This is also available in 2.7 as viewitems().

The operation items() will work for both 2 and 3, but in 2 it will return a list of the dictionary's (key, value) pairs, which will not reflect changes to the dict that happen after the items() call. If you want the 2.x behavior in 3.x, you can call list(d.items()).

Ref: https://bit.ly/37dm0Qo