Python: Passes argument(s) to a function - w3resource
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Python: Passes argument(s) to a function

Python Class ( Basic ): Exercise-6 with Solution

Write a Python function student_data () which will print the id of a student (student_id). If the user passes an argument student_name or student_class the function will print the student name and class.

Sample Solution:

Python Code:

def student_data(student_id, **kwargs):
    print(f'\nStudent ID: {student_id}')
    if 'student_name' in kwargs:
        print(f"Student Name: $ {kwargs['student_name']}")
    
    if 'student_name' and 'student_class' in kwargs:
            print(f"\nStudent Name: $ {kwargs['student_name']}")
            print(f"Student Class: $ {kwargs['student_class']}")

 
student_data(student_id='SV12', student_name='Jean Garner')

student_data(student_id='SV12', student_name='Jean Garner', student_class ='V')

Sample Output:

Student ID: SV12
Student Name: $ Jean Garner

Student ID: SV12
Student Name: $ Jean Garner

Student Name: $ Jean Garner
Student Class: $ V

Flowchart:

Flowchart: Passes argument(s) to a function.

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Previous: Define a Python function student(). Using function attributes display the names of all arguments.
Next: Write a simple Python class named Student and display its type.

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Python: Tips of the Day

The Zip() Function:

>>> students = ('John', 'Mary', 'Mike')
>>> ages = (15, 17, 16)
>>> scores = (90, 88, 82, 17, 14)
>>> for student, age, score in zip(students, ages, scores):
...     print(f'{student}, age: {age}, score: {score}')
... 
John, age: 15, score: 90
Mary, age: 17, score: 88
Mike, age: 16, score: 82
>>> zipped = zip(students, ages, scores)
>>> a, b, c = zip(*zipped)
>>> print(b)
(15, 17, 16)