Python: Frequency of the tuples in a given list

Python Collections: Exercise-23 with Solution

Write a Python program to get the frequency of the tuples in a given list.

Sample Solution:

Python Code:

from collections import Counter
nums = [(['1', '4'], ['4', '1'], ['3', '4'], ['2', '7'], ['6', '8'], ['5','8'], ['6','8'], ['5','7'], ['2','7'])]
print("Original list of tuples:")
result = Counter(tuple(sorted(i)) for i in nums[0])
print("\nTuples","    ","frequency")
for key,val in result.items():
    print(key," ", val)

Sample Output:

Original list of tuples:
[(['1', '4'], ['4', '1'], ['3', '4'], ['2', '7'], ['6', '8'], ['5', '8'], ['6', '8'], ['5', '7'], ['2', '7'])]

Tuples      frequency
('1', '4')   2
('3', '4')   1
('2', '7')   2
('6', '8')   2
('5', '8')   1
('5', '7')   1


Python Collections: Frequency of the tuples in a given list.

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Next: Write a Python program to calculate the maximum aggregate from the list of tuples (pairs).

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Python: Tips of the Day

Returns the symmetric difference between two lists, after applying the provided function to each list element of both:


def tips_symmetric_difference_by(p, q, fn):
  _p, _q = set(map(fn, p)), set(map(fn, q))
  return [item for item in p if fn(item) not in _q] + [item for item in q if fn(item) not in _p]
from math import floor
print(tips_symmetric_difference_by([4.2, 2.4], [4.6, 6.8],floor))


[2.4, 6.8]


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