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Python: Sort a list alphabetically in a dictionary

Python dictionary: Exercise-28 with Solution

Write a Python program to sort a list alphabetically in a dictionary.

Sample Solution:-

Python Code:

num = {'n1': [2, 3, 1], 'n2': [5, 1, 2], 'n3': [3, 2, 4]}
sorted_dict = {x: sorted(y) for x, y in num.items()}
print(sorted_dict)

Sample Output: 

{'n1': [1, 2, 3], 'n2': [1, 2, 5], 'n3': [2, 3, 4]}

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Python: Tips of the Day

Invokes the provided function after ms milliseconds:

Example:

from time import sleep

def tips_delay(fn, ms, *args):
  sleep(ms / 1000)
  return fn(*args)
print(tips_delay(
  lambda x: print(x),
  1000,
  'w3r'
))

Output:

w3r
None