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Python: Replace dictionary values with their average

Python dictionary: Exercise-37 with Solution

Write a Python program to replace dictionary values with their average.

Sample Solution:-

Python Code:

def sum_math_v_vi_average(list_of_dicts):
    for d in list_of_dicts:
        n1 = d.pop('V')
        n2 = d.pop('VI')
        d['V+VI'] = (n1 + n2)/2
    return list_of_dicts 
student_details= [
  {'id' : 1, 'subject' : 'math', 'V' : 70, 'VI' : 82},
  {'id' : 2, 'subject' : 'math', 'V' : 73, 'VI' : 74},
  {'id' : 3, 'subject' : 'math', 'V' : 75, 'VI' : 86}
]
print(sum_math_v_vi_average(student_details))

Sample Output: 

[{'subject': 'math', 'id': 1, 'V+VI': 76.0}, {'subject': 'math', 'id': 2, 'V+VI': 73.5}, {'subject': 'math', '
id': 3, 'V+VI': 80.5}]

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Python Dictionary: Replace dictionary values with their average.

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Python: Tips of the Day

Invokes the provided function after ms milliseconds:

Example:

from time import sleep

def tips_delay(fn, ms, *args):
  sleep(ms / 1000)
  return fn(*args)
print(tips_delay(
  lambda x: print(x),
  1000,
  'w3r'
))

Output:

w3r
None