Python: Create an iteraor to get specified number of permutations of elements
Python Itertools: Exercise-10 with Solution
Write a Python program to create an iterator to get a specified number of permutations of elements.
Sample Solution:
Python Code:
import itertools as it
def permutations_data(iter, length):
return it.permutations(iter, length)
#List
result = permutations_data(['A','B','C','D'], 3)
print("\nIterator to get specified number of permutations of elements:")
for i in result:
print(i)
#String
result = permutations_data("Python", 2)
print("\nIterator to get specified number of permutations of elements:")
for i in result:
print(i)
Sample Output:
Iterator to get specified number of permutations of elements: ('A', 'B', 'C') ('A', 'B', 'D') ('A', 'C', 'B') ('A', 'C', 'D') ('A', 'D', 'B') ('A', 'D', 'C') ('B', 'A', 'C') ('B', 'A', 'D') ('B', 'C', 'A') ('B', 'C', 'D') ('B', 'D', 'A') ('B', 'D', 'C') ('C', 'A', 'B') ('C', 'A', 'D') ('C', 'B', 'A') ('C', 'B', 'D') ('C', 'D', 'A') ('C', 'D', 'B') ('D', 'A', 'B') ('D', 'A', 'C') ('D', 'B', 'A') ('D', 'B', 'C') ('D', 'C', 'A') ('D', 'C', 'B') Iterator to get specified number of permutations of elements: ('P', 'y') ('P', 't') ('P', 'h') ('P', 'o') ('P', 'n') ('y', 'P') ('y', 't') ('y', 'h') ('y', 'o') ('y', 'n') ('t', 'P') ('t', 'y') ('t', 'h') ('t', 'o') ('t', 'n') ('h', 'P') ('h', 'y') ('h', 't') ('h', 'o') ('h', 'n') ('o', 'P') ('o', 'y') ('o', 't') ('o', 'h') ('o', 'n') ('n', 'P') ('n', 'y') ('n', 't') ('n', 'h') ('n', 'o')
Python Code Editor:
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Previous: Write a Python program to split an iterable and generate iterables specified number of times.
Next: Write a Python program to generate combinations of a given length of given iterable.
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Python: Tips of the Day
Inverts a dictionary with non-unique hashable values:
Example:
def tips_collect_dictionary(obj): inv_obj = {} for key, value in obj.items(): inv_obj.setdefault(value, list()).append(key) return inv_obj ages = { "Owen": 25, "Jhon": 25, "Pepe": 15, } print(tips_collect_dictionary(ages))
Output:
{25: ['Owen', 'Jhon'], 15: ['Pepe']}
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