﻿ Python: Create an iteraor to get specified number of permutations of elements - w3resource

# Python: Create an iteraor to get specified number of permutations of elements

## Python Itertools: Exercise-10 with Solution

Write a Python program to create an iterator to get a specified number of permutations of elements.

Sample Solution:

Python Code:

``````import itertools as it
def permutations_data(iter, length):
return it.permutations(iter, length)
#List
result = permutations_data(['A','B','C','D'], 3)
print("\nIterator to get specified number of permutations of elements:")
for i in result:
print(i)

#String
result = permutations_data("Python", 2)
print("\nIterator to get specified number of permutations of elements:")
for i in result:
print(i)
```
```

Sample Output:

```Iterator to get specified number of permutations of elements:
('A', 'B', 'C')
('A', 'B', 'D')
('A', 'C', 'B')
('A', 'C', 'D')
('A', 'D', 'B')
('A', 'D', 'C')
('B', 'A', 'C')
('B', 'A', 'D')
('B', 'C', 'A')
('B', 'C', 'D')
('B', 'D', 'A')
('B', 'D', 'C')
('C', 'A', 'B')
('C', 'A', 'D')
('C', 'B', 'A')
('C', 'B', 'D')
('C', 'D', 'A')
('C', 'D', 'B')
('D', 'A', 'B')
('D', 'A', 'C')
('D', 'B', 'A')
('D', 'B', 'C')
('D', 'C', 'A')
('D', 'C', 'B')

Iterator to get specified number of permutations of elements:
('P', 'y')
('P', 't')
('P', 'h')
('P', 'o')
('P', 'n')
('y', 'P')
('y', 't')
('y', 'h')
('y', 'o')
('y', 'n')
('t', 'P')
('t', 'y')
('t', 'h')
('t', 'o')
('t', 'n')
('h', 'P')
('h', 'y')
('h', 't')
('h', 'o')
('h', 'n')
('o', 'P')
('o', 'y')
('o', 't')
('o', 'h')
('o', 'n')
('n', 'P')
('n', 'y')
('n', 't')
('n', 'h')
('n', 'o')
```

Python Code Editor:

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## Python: Tips of the Day

Inverts a dictionary with non-unique hashable values:

Example:

```def tips_collect_dictionary(obj):
inv_obj = {}
for key, value in obj.items():
inv_obj.setdefault(value, list()).append(key)
return inv_obj
ages = {
"Owen": 25,
"Jhon": 25,
"Pepe": 15,
}
print(tips_collect_dictionary(ages))
```

Output:

```{25: ['Owen', 'Jhon'], 15: ['Pepe']}
```

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