Python: Find the maximum, minimum aggregation pair in given list of integers
Python Itertools: Exercise-28 with Solution
Write a Python program to find the maximum, minimum aggregation pair in a given list of integers.
Sample Solution:
Python Code:
from itertools import combinations
def max_aggregate(l_data):
max_pair = max(combinations(l_data, 2), key = lambda pair: pair[0] + pair[1])
min_pair = min(combinations(l_data, 2), key = lambda pair: pair[0] + pair[1])
return max_pair,min_pair
nums = [1,3,4,5,4,7,9,11,10,9]
print("Original list:")
print(nums)
result = max_aggregate(nums)
print("\nMaximum aggregation pair of the said list of tuple pair:")
print(result[0])
print("\nMinimum aggregation pair of the said list of tuple pair:")
print(result[1])
Sample Output:
Original list: [1, 3, 4, 5, 4, 7, 9, 11, 10, 9] Maximum aggregation pair of the said list of tuple pair: (11, 10) Minimum aggregation pair of the said list of tuple pair: (1, 3)
Python Code Editor:
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Previous: Write a Python program to chose specified number of colours from three different colours and generate the unique combinations.
Next: Write a Python program to interleave multiple lists of the same length. Use itertools module.
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Python: Tips of the Day
Inverts a dictionary with non-unique hashable values:
Example:
def tips_collect_dictionary(obj): inv_obj = {} for key, value in obj.items(): inv_obj.setdefault(value, list()).append(key) return inv_obj ages = { "Owen": 25, "Jhon": 25, "Pepe": 15, } print(tips_collect_dictionary(ages))
Output:
{25: ['Owen', 'Jhon'], 15: ['Pepe']}
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