Python: Split a given list into specified sized chunks using itertools module
Python Itertools: Exercise-40 with Solution
Write a Python program to split a given list into specified sized chunks using the itertools module.
Sample Solution:
Python Code:
from itertools import islice
def split_list(lst, n):
lst = iter(lst)
result = iter(lambda: tuple(islice(lst, n)), ())
return list(result)
nums = [12,45,23,67,78,90,45,32,100,76,38,62,73,29,83]
print("Original list:")
print(nums)
n = 3
print("\nSplit the said list into equal size",n)
print(split_list(nums,n))
n = 4
print("\nSplit the said list into equal size",n)
print(split_list(nums,n))
n = 5
print("\nSplit the said list into equal size",n)
print(split_list(nums,n))
Sample Output:
Original list: [12, 45, 23, 67, 78, 90, 45, 32, 100, 76, 38, 62, 73, 29, 83] Split the said list into equal size 3 [(12, 45, 23), (67, 78, 90), (45, 32, 100), (76, 38, 62), (73, 29, 83)] Split the said list into equal size 4 [(12, 45, 23, 67), (78, 90, 45, 32), (100, 76, 38, 62), (73, 29, 83)] Split the said list into equal size 5 [(12, 45, 23, 67, 78), (90, 45, 32, 100, 76), (38, 62, 73, 29, 83)]
Python Code Editor:
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Python: Tips of the Day
Inverts a dictionary with non-unique hashable values:
Example:
def tips_collect_dictionary(obj):
inv_obj = {}
for key, value in obj.items():
inv_obj.setdefault(value, list()).append(key)
return inv_obj
ages = {
"Owen": 25,
"Jhon": 25,
"Pepe": 15,
}
print(tips_collect_dictionary(ages))
Output:
{25: ['Owen', 'Jhon'], 15: ['Pepe']}
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