﻿ Python: Count the even, odd numbers in a given array of integers using Lambda - w3resource

# Python: Count the even, odd numbers in a given array of integers using Lambda

## Python Lambda: Exercise-13 with Solution

Write a Python program to count the even, odd numbers in a given array of integers using Lambda.

Sample Solution:

Python Code :

``````array_nums = [1, 2, 3, 5, 7, 8, 9, 10]
print("Original arrays:")
print(array_nums)
odd_ctr = len(list(filter(lambda x: (x%2 != 0) , array_nums)))
even_ctr = len(list(filter(lambda x: (x%2 == 0) , array_nums)))
print("\nNumber of even numbers in the above array: ", even_ctr)
print("\nNumber of odd numbers in the above array: ", odd_ctr)
``````

Sample Output:

```Original arrays:
[1, 2, 3, 5, 7, 8, 9, 10]

Number of even numbers in the above array:  3

Number of odd numbers in the above array:  5
```

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## Python: Tips of the Day

Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

```from functools import lru_cache

@lru_cache(maxsize=None)
def fibo(a):
if a <= 1:
return a
else:
return fibo(a-1) + fibo(a-2)

for i in range(20):
print(fibo(i), end="|")

print("\n\n", fibo.cache_info())
```

Output:

```0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181|

CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)```