Python: Count the even, odd numbers in a given array of integers using Lambda
Python Lambda: Exercise-13 with Solution
Write a Python program to count the even, odd numbers in a given array of integers using Lambda.
Python Code :
array_nums = [1, 2, 3, 5, 7, 8, 9, 10] print("Original arrays:") print(array_nums) odd_ctr = len(list(filter(lambda x: (x%2 != 0) , array_nums))) even_ctr = len(list(filter(lambda x: (x%2 == 0) , array_nums))) print("\nNumber of even numbers in the above array: ", even_ctr) print("\nNumber of odd numbers in the above array: ", odd_ctr)
Original arrays: [1, 2, 3, 5, 7, 8, 9, 10] Number of even numbers in the above array: 3 Number of odd numbers in the above array: 5
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Python: Tips of the Day
Python: Cache results with decorators
There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.
Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.
from functools import lru_cache @lru_cache(maxsize=None) def fibo(a): if a <= 1: return a else: return fibo(a-1) + fibo(a-2) for i in range(20): print(fibo(i), end="|") print("\n\n", fibo.cache_info())
0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181| CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)
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