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Python: Find the second lowest grade of any student(s) from the given names and grades of each student using lists and Lambda

Python Lambda: Exercise-16 with Solution

Write a Python program to find the second lowest grade of any student(s) from the given names and grades of each student using lists and lambda. Input number of students, names and grades of each student.

Note: If there are multiple students with the same grade then print each name alphabetically.

Sample Solution:

Python Code :

students = []
sec_name = []
second_low = 0
n = int(input("Input number of students: "))
for _ in range(n):
   s_name = input("Name: ")
   score = float(input("Grade: "))
   students.append([s_name,score])
print("\nNames and Grades of all students:")
print(students)
order =sorted(students, key = lambda x: int(x[1]))
for i in range(n):
   if order[i][1] != order[0][1]:
       second_low = order[i][1]
       break
print("\nSecond lowest grade: ",second_low)
sec_student_name = [x[0] for x in order if x[1] == second_low]
sec_student_name.sort()
print("\nNames:")
for s_name in sec_student_name:
   print(s_name)

Sample Output:

Input number of students:  5
Name:  S ROY
Grade:  1
Name:  B BOSE
Grade:  3
Name:  N KAR
Grade:  2
Name:  C DUTTA
Grade:  1
Name:  G GHOSH
Grade:  1

Names and Grades of all students:
[['S ROY', 1.0], ['B BOSE', 3.0], ['N KAR', 2.0], ['C DUTTA', 1.0], ['G GHOSH', 1.0]]

Second lowest grade:  2.0

Names:
N KAR

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Python: Tips of the Day

Returns all the elements of a list except the last one

Example:

def tips_initial(lst):
  return lst[0:-1]

print(tips_initial([1, 2, 3, 4]))

Output:

[1, 2, 3]