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Python: Find the numbers of a given string and store them in a list, display the numbers which are bigger than the length of the list in sorted form

Python Lambda: Exercise-20 with Solution

Write a Python program to find the numbers of a given string and store them in a list, display the numbers which are bigger than the length of the list in sorted form. Use lambda function to solve the problem.

Sample Solution:

Python Code :

str1 = "sdf 23 safs8 5 sdfsd8 sdfs 56 21sfs 20 5"
print("Original string: ",str1)
str_num=[i for i in str1.split(' ')]
lenght=len(str_num)
numbers=sorted([int(x) for x in str_num if x.isdigit()])
print('Numbers in sorted form:')
for i in ((filter(lambda x:x>lenght,numbers))):
    print(i,end=' ')

Sample Output:

Original string:  sdf 23 safs8 5 sdfsd8 sdfs 56 21sfs 20 5
Numbers in sorted form:
20 23 56 

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Previous: Write a Python program to find all anagrams of a string in a given list of strings using lambda.
Next: Write a Python program that multiply each number of given list with a given number using lambda function. Print the result.

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Python: Tips of the Day

Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

from functools import lru_cache

@lru_cache(maxsize=None)
def fibo(a):
    if a <= 1:
        return a
    else:
        return fibo(a-1) + fibo(a-2)

for i in range(20):
    print(fibo(i), end="|")

print("\n\n", fibo.cache_info())

Output:

0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181|

 CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)