Python: Count float number in a given mixed list using lambda
Python Lambda: Exercise-32 with Solution
Write a Python program to count float number in a given mixed list using lambda.
Python Code :
def count_integer(list1): ert = list(map(lambda i: isinstance(i, float), list1)) result = len([e for e in ert if e]) return result list1 = [1, 'abcd', 3.12, 1.2, 4, 'xyz', 5, 'pqr', 7, -5, -12.22] print("Original list:") print(list1) print("\nNumber of floats in the said mixed list:") print(count_integer(list1))
Original list: [1, 'abcd', 3.12, 1.2, 4, 'xyz', 5, 'pqr', 7, -5, -12.22] Number of floats in the said mixed list: 3
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Python: Cache results with decorators
There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.
Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.
from functools import lru_cache @lru_cache(maxsize=None) def fibo(a): if a <= 1: return a else: return fibo(a-1) + fibo(a-2) for i in range(20): print(fibo(i), end="|") print("\n\n", fibo.cache_info())
0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181| CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)
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