w3resource

Python: Count float number in a given mixed list using lambda

Python Lambda: Exercise-32 with Solution

Write a Python program to count float number in a given mixed list using lambda.

Sample Solution:

Python Code :

def count_integer(list1):
    ert = list(map(lambda i: isinstance(i, float), list1)) 
    result = len([e for e in ert if e])         
    return result
list1 = [1, 'abcd', 3.12, 1.2, 4, 'xyz', 5, 'pqr', 7, -5, -12.22]
print("Original list:")
print(list1)
print("\nNumber of floats in the said mixed list:")
print(count_integer(list1))

Sample Output:

Original list:
[1, 'abcd', 3.12, 1.2, 4, 'xyz', 5, 'pqr', 7, -5, -12.22]

Number of floats in the said mixed list:
3

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to extract specified size of strings from a give list of string values using lambda.
Next: Write a Python program to check whether a given string contains a capital letter, a lower case letter, a number and a minimum length using lambda.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz



Python: Tips of the Day

Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

from functools import lru_cache

@lru_cache(maxsize=None)
def fibo(a):
    if a <= 1:
        return a
    else:
        return fibo(a-1) + fibo(a-2)

for i in range(20):
    print(fibo(i), end="|")

print("\n\n", fibo.cache_info())

Output:

0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181|

 CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)