Python: Remove all elements from a given list present in another list using lambda

Python Lambda: Exercise-38 with Solution

Write a Python program to remove all elements from a given list present in another list using lambda.

Sample Solution:

Python Code :

def index_on_inner_list(list1, list2):
    result = list(filter(lambda x: x not in list2, list1))
    return result
list1 = [1,2,3,4,5,6,7,8,9,10]
list2 = [2,4,6,8]
print("Original lists:")
print("list1:", list1)
print("list2:", list2)
print("\nRemove all elements from 'list1' present in 'list2:")
print(index_on_inner_list(list1, list2))

Sample Output:

Original lists:
list1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
list2: [2, 4, 6, 8]

Remove all elements from 'list1' present in 'list2:
[1, 3, 5, 7, 9, 10]

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Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

from functools import lru_cache

def fibo(a):
    if a <= 1:
        return a
        return fibo(a-1) + fibo(a-2)

for i in range(20):
    print(fibo(i), end="|")

print("\n\n", fibo.cache_info())



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