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Python: Find the nested lists elements, which are present in another list using lambda

Python Lambda: Exercise-40 with Solution

Write a Python program to find the nested lists elements, which are present in another list using lambda.

Sample Solution:

Python Code :

def intersection_nested_lists(l1, l2):
    result = [list(filter(lambda x: x in l1, sublist)) for sublist in l2]
    return result
nums1 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
nums2 = [[12, 18, 23, 25, 45], [7, 11, 19, 24, 28], [1, 5, 8, 18, 15, 16]]
print("\nOriginal lists:")
print(nums1)
print(nums2)
print("\nIntersection of said nested lists:")
print(intersection_nested_lists(nums1, nums2))

Sample Output:

Original lists:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
[[12, 18, 23, 25, 45], [7, 11, 19, 24, 28], [1, 5, 8, 18, 15, 16]]

Intersection of said nested lists:
[[12], [7, 11], [1, 5, 8]]

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Previous: Write a Python program to find the elements of a given list of strings that contain specific substring using lambda.
Next: Write a Python program to reverse strings in a given list of string values using lambda.

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Python: Tips of the Day

Python: Cache results with decorators

There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.

Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.

from functools import lru_cache

@lru_cache(maxsize=None)
def fibo(a):
    if a <= 1:
        return a
    else:
        return fibo(a-1) + fibo(a-2)

for i in range(20):
    print(fibo(i), end="|")

print("\n\n", fibo.cache_info())

Output:

0|1|1|2|3|5|8|13|21|34|55|89|144|233|377|610|987|1597|2584|4181|

 CacheInfo(hits=36, misses=20, maxsize=None, currsize=20)