Python: Find the nested lists elements, which are present in another list using lambda
Python Lambda: Exercise-40 with Solution
Write a Python program to find the nested lists elements, which are present in another list using lambda.
Python Code :
def intersection_nested_lists(l1, l2): result = [list(filter(lambda x: x in l1, sublist)) for sublist in l2] return result nums1 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14] nums2 = [[12, 18, 23, 25, 45], [7, 11, 19, 24, 28], [1, 5, 8, 18, 15, 16]] print("\nOriginal lists:") print(nums1) print(nums2) print("\nIntersection of said nested lists:") print(intersection_nested_lists(nums1, nums2))
Original lists: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14] [[12, 18, 23, 25, 45], [7, 11, 19, 24, 28], [1, 5, 8, 18, 15, 16]] Intersection of said nested lists: [, [7, 11], [1, 5, 8]]
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Python: Cache results with decorators
There is a great way to cache functions with decorators in Python. Caching will help save time and precious resources when there is an expensive function at hand.
Implementation is easy, just import lru_cache from functools library and decorate your function using @lru_cache.
from functools import lru_cache @lru_cache(maxsize=None) def fibo(a): if a <= 1: return a else: return fibo(a-1) + fibo(a-2) for i in range(20): print(fibo(i), end="|") print("\n\n", fibo.cache_info())
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