﻿ Python: Calculate the average value of the numbers in a given tuple of tuples using lambda - w3resource # Python: Calculate the average value of the numbers in a given tuple of tuples using lambda

## Python Lambda: Exercise-44 with Solution

Write a Python program to calculate the average value of the numbers in a given tuple of tuples using lambda.

Sample Solution:

Python Code :

``````def average_tuple(nums):
result = tuple(map(lambda x: sum(x) / float(len(x)), zip(*nums)))
return result

nums = ((10, 10, 10), (30, 45, 56), (81, 80, 39), (1, 2, 3))
print ("Original Tuple: ")
print(nums)
print("\nAverage value of the numbers of the said tuple of tuples:\n",average_tuple(nums))
nums = ((1, 1, -5), (30, -15, 56), (81, -60, -39), (-10, 2, 3))
print ("\nOriginal Tuple: ")
print(nums)
print("\nAverage value of the numbers of the said tuple of tuples:\n",average_tuple(nums))

``````

Sample Output:

```Original Tuple:
((10, 10, 10), (30, 45, 56), (81, 80, 39), (1, 2, 3))

Average value of the numbers of the said tuple of tuples:
(30.5, 34.25, 27.0)

Original Tuple:
((1, 1, -5), (30, -15, 56), (81, -60, -39), (-10, 2, 3))

Average value of the numbers of the said tuple of tuples:
(25.5, -18.0, 3.75)
```

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## Python: Tips of the Day

Splits values into two groups. If an element in filter is True, the corresponding element in the collection belongs to the first group; otherwise, it belongs to the second group

Example:

```def tips_bifurcate(lst, filter):
return [
[x for i, x in enumerate(lst) if filter[i] == True],
[x for i, x in enumerate(lst) if filter[i] == False]
]

print(tips_bifurcate(['little', 'boo', 'peep', 'sat'], [True, True, False, True]))
```

Output:

```[['little', 'boo', 'sat'], ['peep']]
```