w3resource

Python: Find the difference between consecutive numbers in a given list

Python List: Exercise - 104 with Solution

Write a Python program to find the difference between consecutive numbers in a given list.

Sample Solution:

Python Code:

def diff_consecutive_nums(nums):
    result = [b-a for a, b in zip(nums[:-1], nums[1:])]
    return result

nums1 = [1, 1, 3, 4, 4, 5, 6, 7]
print("Original list:")
print(nums1)
print("Difference between consecutive numbers of the said list:") 
print(diff_consecutive_nums(nums1))

nums2 = [4, 5, 8, 9, 6, 10]
print("\nOriginal list:")
print(nums2)
print("Difference between consecutive numbers of the said list:") 
print(diff_consecutive_nums(nums2))

Sample Output:

Original list:
[1, 1, 3, 4, 4, 5, 6, 7]
Difference between consecutive numbers of the said list:
[0, 2, 1, 0, 1, 1, 1]

Original list:
[4, 5, 8, 9, 6, 10]
Difference between consecutive numbers of the said list:
[1, 3, 1, -3, 4]

Pictorial Presentation:

Python List: Find the difference between consecutive numbers in a given list.

Flowchart:

Flowchart: Find the difference between consecutive numbers in a given list.

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to extract specified number of elements from a given list, which follows each other continuously.
Next: Write a Python program to compute average of two given lists.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.

Python: Tips of the Day

Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:

Example:

def tips_check_prop(fn, prop):
  return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}

print(check_age(user))

Output:

True 

 





We are closing our Disqus commenting system for some maintenanace issues. You may write to us at reach[at]yahoo[dot]com or visit us at Facebook