Python: Check whether a specified list is sorted or not
Python List: Exercise - 112 with Solution
Write a Python program to check whether a specified list is sorted or not.
Sample Solution:
Python Code:
def is_sort_list(nums):
result = all(nums[i] <= nums[i+1] for i in range(len(nums)-1))
return result
nums1 = [1,2,4,6,8,10,12,14,16,17]
print ("Original list:")
print(nums1)
print("\nIs the said list is sorted!")
print(is_sort_list(nums1))
nums2 = [2,3,8,4,7,9,8,2,6,5,1,6,1,2,3,4,6,9,1,2]
print ("\nOriginal list:")
print(nums1)
print("\nIs the said list is sorted!")
print(is_sort_list(nums2))
Sample Output:
Original list: [1, 2, 4, 6, 8, 10, 12, 14, 16, 17] Is the said list is sorted! True Original list: [1, 2, 4, 6, 8, 10, 12, 14, 16, 17] Is the said list is sorted! False
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Python: Tips of the Day
Creates a list of elements, grouped based on the position in the original lists:
Example:
def tips_zip(*args, fill_value=None): max_length = max([len(lst) for lst in args]) result = [] for i in range(max_length): result.append([ args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args)) ]) return result print(tips_zip(['a', 'b'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False])) print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))
Output:
[['a', 1, True], ['b', 2, False]] [['a', 1, True], [None, 2, False]] [['a', 1, True], ['1', 2, False]]
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